Question:medium

If \( z = x + iy \) is a complex number such that \( |z - 1| = |z + 1| \), then the locus of \( z \) represents:

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\textbf{Tip:} When the modulus of distances from two points is equal, the locus is the perpendicular bisector of the segment joining them.
Updated On: Nov 26, 2025
  • A circle with center at origin
  • The real axis
  • The imaginary axis
  • A line parallel to the x-axis
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The Correct Option is C

Solution and Explanation

For the complex number \( z = x + iy \), we seek the locus defined by \( |z - 1| = |z + 1| \). This condition signifies that the distance from \( z \) to the point \( 1 \) is equivalent to its distance to the point \( -1 \).

The distances are calculated as follows:

\(|z - 1| = \sqrt{(x - 1)^2 + y^2}\) and \(|z + 1| = \sqrt{(x + 1)^2 + y^2}\).

Equating these expressions yields:\(\sqrt{(x - 1)^2 + y^2} = \sqrt{(x + 1)^2 + y^2}\).

Squaring both sides to remove the radicals results in:\((x - 1)^2 + y^2 = (x + 1)^2 + y^2\).

Expanding both sides gives:\(x^2 - 2x + 1 + y^2 = x^2 + 2x + 1 + y^2\).

Canceling identical terms (\(x^2\), \(y^2\), \(1\)) from each side simplifies the equation to:\(-2x = 2x\).

Combining like terms produces:\(4x = 0\).

Solving for \(x\) yields:\(x = 0\).

Therefore, any complex number \(z = x + iy\) satisfying this condition must have an \(x\)-component of 0. This means \(z\) lies on the line defined by \(x = 0\), which is the imaginary axis.

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