Question:medium

If \( z = \tan(y + ax) + \sqrt{y} - ax \), then \( z_{xx} - a^2 z_{yy} \) is equal to

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If $z=tan(y+ax)+\sqrty-ax$, then $zxx-azyy$ is equal to
Updated On: Apr 15, 2026
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  • $z_{x}+z_{y}$
  • $z_{x}z_{y}$
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The Correct Option is A

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