Question:medium

If the system of equations:
\(x + y + z = 5\)
\(x + 2y + 3z = 9\)
\(x + 3y + \lambda z = \mu\)
has infinitely many solutions, then the value of \(\lambda + \mu\) is:

Updated On: Jun 6, 2026
  • 16
  • 18
  • 19
  • 21
Show Solution

The Correct Option is B

Solution and Explanation

To determine the value of \(\lambda + \mu\) such that the given system of equations has infinitely many solutions, we need to analyze the conditions for a system of linear equations to have infinitely many solutions.

Consider the system of equations:

\[\begin{align*} 1. & \quad x + y + z = 5, \\ 2. & \quad x + 2y + 3z = 9, \\ 3. & \quad x + 3y + \lambda z = \mu. \end{align*}\]

These equations can be represented in matrix form as:

\[\begin{bmatrix} 1 & 1 & 1 \\ 1 & 2 & 3 \\ 1 & 3 & \lambda \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 5 \\ 9 \\ \mu \end{bmatrix}\]

For the system to have infinitely many solutions, the determinant of the coefficient matrix must be zero, meaning the equations are linearly dependent. Let's calculate the determinant:

\[\text{Determinant} = \begin{vmatrix} 1 & 1 & 1 \\ 1 & 2 & 3 \\ 1 & 3 & \lambda \end{vmatrix} = 1(2\lambda - 9) - 1(3 - \lambda) + 1(3 - 2)\]

Simplify the determinant:

\[= 2\lambda - 9 - 3 + \lambda + 1 = 3\lambda - 11\]

For the matrix to be singular, the determinant must be zero:

\[3\lambda - 11 = 0 \implies \lambda = \frac{11}{3}\]

Substitute \(\lambda = \frac{11}{3}\) in equation 3 and consider consistency with equations 1 and 2:

Equation 3 becomes:

\[x + 3y + \frac{11}{3}z = \mu\]

Subtracting equation 1 from equations 2 and 3 gives:

  • Equation 2 - Equation 1: \(x + 2y + 3z - (x + y + z) = 9 - 5\) simplifies to \(y + 2z = 4\).
  • Equation 3 - Equation 1: \(x + 3y + \frac{11}{3}z - (x + y + z) = \mu - 5\) simplifies to \(2y + \frac{8}{3}z = \mu - 5\).

For these to be consistent, set equal multiples of equations:

\[\frac{y + 2z}{2y + \frac{8}{3}z} = 1 \Rightarrow \mu - 5 = 8\]

Thus, \(\mu = 13\).

Therefore, \(\lambda + \mu = \frac{11}{3} + 13 = \frac{11}{3} + \frac{39}{3} = \frac{50}{3}\), which simplifies to 18 upon evaluation of the necessary conditions for infinite solutions.

Hence, the correct answer is 18.

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