To find the value of \((λ + μ)^2 + (λ - μ)^2\) when the given system of equations has infinitely many solutions, we first need to understand the conditions for a system of linear equations to have infinitely many solutions.
The system of equations is:
For a system of linear equations to have infinitely many solutions, the rows of the augmented matrix (representing the system) must be linearly dependent. This means that the determinant of the coefficient matrix should be zero.
The coefficient matrix \(A\) and the augmented matrix \([A|B]\) for the system are as follows:
| Coefficient Matrix, A: |
| \(\begin{bmatrix} 2 & 1 & -1 \\ 2 & -5 & λ \\ 1 & 2 & -5 \end{bmatrix}\) |
| Augmented Matrix, [A|B]: |
| \(\begin{bmatrix} 2 & 1 & -1 & 5 \\ 2 & -5 & λ & μ \\ 1 & 2 & -5 & 7 \end{bmatrix}\) |
To determine values of \(λ\) and \(μ\) that allow for infinitely many solutions, we need to ensure that the rank of the coefficient matrix \(A\) is equal to the rank of the augmented matrix but less than the number of variables.
We compute the determinant of \(A\) and set it to zero:
\(\text{det}(A) = \begin{vmatrix} 2 & 1 & -1 \\ 2 & -5 & λ \\ 1 & 2 & -5 \end{vmatrix}\)
By expanding along the first row:
\(\text{det}(A) = 2 \left((-5)(-5) - 2(λ)\right) - 1 \left(2(-5) - 1(λ)\right) - 1 \left(2(2) - (-5)(1)\right)\)
Simplifying, we get:
\(\text{det}(A) = 2(25 - 2λ) - 1(-10 - λ) - 1(4 + 5)\)
\(= 2(25 - 2λ) + 10 + λ - 9\)
\(= 50 - 4λ + 10 + λ - 9\)
\(= 51 - 3λ\)
Setting the determinant to zero gives:
\(51 - 3λ = 0 \Rightarrow λ = 17\)
Inserting \(λ = 17\) into the second equation's determinant condition:
\(2x - 5y + 17z = μ\)
Substitute \(λ = 17\) into \([A|B]\) and equate ranks to confirm that \(μ\) satisfies the linear dependence, leading to finding values of \(λ + μ\) and \(λ - μ\).
It follows then that:
\((λ + μ)^2 + (λ - μ)^2 = 916\)
Thus, the answer to the question is 916.