Question:medium

If the standard reduction potentials of A, B, C are respectively $0.68\text{V}$, $-2.54\text{V}$ and $-0.50\text{V}$, then the order of their reducing power is

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A highly negative reduction potential means the element "hates" gaining electrons and "loves" giving them away. Lithium has the most negative potential in the periodic table, making it the strongest reducing agent.
  • $A \gt B \gt C$
  • $A \gt C \gt B$
  • $C \gt B \gt A$
  • $B \gt C \gt A$
Show Solution

The Correct Option is D

Solution and Explanation

1. Core Principle: The lower (more negative) the standard reduction potential of an element, the more easily it is oxidized, and consequently, the stronger its reducing power.

2. Comparing the Given Potentials:

• $E^0_A = 0.68\text{V}$ (Highest value) [cite: 74]

• $E^0_B = -2.54\text{V}$ (Lowest/Most negative value) [cite: 74]

• $E^0_C = -0.50\text{V}$ (Intermediate value) [cite: 74]

3. Determining the Order: Since a lower potential means higher reducing power:

• $B$ ($-2.54\text{V}$) has the highest reducing power[cite: 74].

• $C$ ($-0.50\text{V}$) has intermediate reducing power[cite: 74].

• $A$ ($0.68\text{V}$) has the lowest reducing power[cite: 74].
The correct decreasing order of reducing power is $B \gt C \gt A$[cite: 74].
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