If the solution of the differential equation \(\frac{dy}{dx} = \frac{\alpha x^2 + 4x - 4}{2y - 4}\), when \(y(1) = 3\), is \(y^2 - 4y = x^3 + 2x^2 - 4x + c\), then the value of \(\alpha\) is equal to
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In questions where the solution form is given, you don't always need to solve for the constant \(c\) unless specifically asked. Focus on equating the coefficients of corresponding powers of \(x\) or \(y\).