If the polar co-ordinates of a point are $\left(\sqrt{2}, \frac{\pi}{4}\right)$, then its Cartesian co-ordinates are
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An angle of $\frac{\pi}{4}$ means the point lies exactly on the line $y = x$ in the first quadrant. This instantly eliminates any options where the $x$ and $y$ coordinates are not identical and positive!
Step 1: Note the polar data. The point is given as $\left(r,\theta\right)=\left(\sqrt{2},\frac{\pi}{4}\right)$ and we want Cartesian $(x,y)$. Step 2: Recall the conversion. $x=r\cos\theta$ and $y=r\sin\theta$. Step 3: Values at $\frac{\pi}{4}$. $\cos\frac{\pi}{4}=\frac{1}{\sqrt{2}}$ and $\sin\frac{\pi}{4}=\frac{1}{\sqrt{2}}$. Step 4: Find $x$. $x=\sqrt{2}\times\frac{1}{\sqrt{2}}=1$. Step 5: Find $y$. $y=\sqrt{2}\times\frac{1}{\sqrt{2}}=1$. Step 6: State the point. The Cartesian coordinates are $(1,1)$, which is option (4). \[ \boxed{(x,y)=(1,1)} \]