Given:
A(4, 5), B(m, 6), C(4, 3), D(1, n) are the vertices of parallelogram ABCD in order.
In a parallelogram, the diagonals bisect each other.
So midpoint of AC = midpoint of BD.
-----------------------------
Step 1: Midpoint of AC
A(4,5), C(4,3)
Midpoint of AC =
\[
\left( \frac{4+4}{2},\ \frac{5+3}{2} \right)
=
(4,\ 4)
\]
-----------------------------
Step 2: Midpoint of BD
B(m,6), D(1,n)
Midpoint of BD =
\[
\left( \frac{m+1}{2},\ \frac{6+n}{2} \right)
\]
-----------------------------
Step 3: Equate the midpoints
Compare x-coordinates:
\[
\frac{m+1}{2} = 4
\]
Multiply by 2:
\[
m + 1 = 8
\]
\[
m = 7
\]
Compare y-coordinates:
\[
\frac{6+n}{2} = 4
\]
Multiply by 2:
\[
6 + n = 8
\]
\[
n = 2
\]
-----------------------------
Final Answers:
\[
\boxed{m = 7,\ n = 2}
\]