The correct option is (A): 0.3%
R=\frac{pl}{A}
\frac{\triangle{R}}{R}=\frac{\triangle{l}}{l}+2\frac{\triangle{d}}{d}
=0.3%
A battery of \( 6 \, \text{V} \) is connected to the circuit as shown below. The current \( I \) drawn from the battery is: