If the moment of inertia of a thin circular ring about an axis passing through its edge and perpendicular to its plane is I, then the moment of inertia of the ring about its diameter is
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Standard M.I. for Ring:
Center, perp: $MR^2$.
Diameter: $MR^2/2$.
Tangent, in plane: $3/2 MR^2$.
Tangent, perp: $2MR^2$.