Question:medium
If the lines \( \frac{x+3}{-3} = \frac{y-1}{k} = \frac{z-5}{5} \) and \( \frac{x+1}{-1} = \frac{y-2}{2} = \frac{z-5}{5} \) are coplanar, then the value of \( k \) is
If the lines \( \frac{x+3}{-3} = \frac{y-1}{k} = \frac{z-5}{5} \) and \( \frac{x+1}{-1} = \frac{y-2}{2} = \frac{z-5}{5} \) are coplanar, then the value of \( k \) is
Show Hint
Scalar triple product zero ⇒ coplanar lines.
Updated On: Apr 30, 2026
- \(1\)
- \(2\)
- \(3\)
- \(4\)
- \(5\)
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The Correct Option is B
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