If the length of a thin uniform rod is 'L' and the radius of gyration of the rod about an axis perpendicular to its length and passing through one end is K, then K:L=
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Remember the moments of inertia for common shapes. For a thin rod:
- About the center: $I_c = ML^2/12$.
- About one end: $I_{end} = ML^2/3$.
You can derive the second from the first using the parallel axis theorem: $I_{end} = I_c + M(L/2)^2 = ML^2/12 + ML^2/4 = ML^2/3$.