Question:medium
A particle is moving in circular path of radius r speed v such that speed is proportional to radius as \(V∝ r^{\frac{3}{2}}\). Then how does time period of revolution depends on r i.e Trn then \(n\) is.
A particle is moving in circular path of radius r speed v such that speed is proportional to radius as \(V∝ r^{\frac{3}{2}}\). Then how does time period of revolution depends on r i.e Trn then \(n\) is.
Updated On: Apr 19, 2026
- \(-\frac{1}{2}\)
- \(\frac{5}{2}\)
- \(-\frac{5}{2}\)
- \(\frac{1}{2}\)
Show Solution
The Correct Option is B
Solution and Explanation
Option (B) is correct: \( \frac{5}{2} \)
Was this answer helpful?
2
Top Questions on System of Particles & Rotational Motion
- A body of mass 10 kg is moving with a speed of 5 m/s. What is the momentum of the body?
- VITEEE - 2025
- Physics
- System of Particles & Rotational Motion
- A particle moves in a straight line so that its displacement $x$ at any time $t$ is given by $x^2 = 1 + t^2$.
Its acceleration at any time $t$ is $x^{-n}$ where $n =$ ____.- JEE Main - 2024
- Physics
- System of Particles & Rotational Motion
The center of mass of a thin rectangular plate (fig - x) with sides of length \( a \) and \( b \), whose mass per unit area (\( \sigma \)) varies as \( \sigma = \sigma_0 \frac{x}{ab} \) (where \( \sigma_0 \) is a constant), would be
- JEE Main - 2025
- Physics
- System of Particles & Rotational Motion
- The moment of inertia of a solid disc rotating along its diameter is 2.5 times higher than the moment of inertia of a ring rotating in a similar way. The moment of inertia of a solid sphere which has the same radius as the disc and rotating in similar way, is \( n \) times higher than the moment of inertia of the given ring. Here, \( n = \):
- JEE Main - 2025
- Physics
- System of Particles & Rotational Motion
- Want to practice more? Try solving extra ecology questions todayView All Questions
