If the internal resistance of the cell is negligible, then the current flowing through the circuit is
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When analyzing a series circuit, the total resistance is simply the sum of individual resistances. The current is found using Ohm's law or Kirchhoff’s Voltage Law.
Step 1: Understanding the Question:
The circuit contains diodes and resistors. We must determine which diode is forward-biased and which is reverse-biased based on the battery polarity to find the effective path of the current. Step 2: Key Formula or Approach:
1. Forward bias: Diode conducts (acts as a wire if ideal).
2. Reverse bias: Diode does not conduct (acts as an open switch).
3. Ohm's Law: \( I = \frac{V}{R_{total}} \). Step 3: Detailed Explanation:
The battery is 5V with the positive terminal connected to the right side of the circuit.
- Top branch: \( D_2 \) has its cathode (\( n \)-side) facing the positive terminal. It is reverse-biased and does not conduct.
- Middle branch: \( D_1 \) has its anode (\( p \)-side) facing the positive terminal. It is forward-biased and conducts.
Current flows through the 20 \( \Omega \) resistor, then entirely through the middle branch containing the 30 \( \Omega \) resistor.
Total resistance \( R = 20 + 30 = 50\text{ } \Omega \).
Current \( I = \frac{5}{50} = 0.10\text{ A} \). Step 4: Final Answer:
The current flowing through the circuit is 0.10 A.
