Question:medium

If the electric field of a plane electromagnetic wave is $E_z = 60\sin(0.5\times 10^3x + 1.5\times 10^{11}t)$ Vm$^{-1}$, then the magnetic field of the wave is

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In a plane electromagnetic wave, $\vec{E}$ and $\vec{B}$ are perpendicular to each other and to the direction of propagation ($\vec{v}$). The direction of propagation is given by $\vec{v} \propto \vec{E} \times \vec{B}$, and the ratio of their amplitudes is $E_0/B_0 = c$.

Updated On: Mar 30, 2026

$B_y = 2\times 10^{-7}\sin(0.5\times 10^3x + 1.5\times 10^{11}t)$ T
$B_z = 2\times 10^{-7}\sin(0.5\times 10^3x + 1.5\times 10^{11}t)$ T
$B_x = 180\times 10^8\sin(0.5\times 10^3x + 1.5\times 10^{11}t)$ T
$B_y = 180\times 10^8\sin(0.5\times 10^3x + 1.5\times 10^{11}t)$ T

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The Correct Option is A

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