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If the distance between the foci of an ellipse is 6 and the length of the minor axis is 8, then the eccentricity is
If the distance between the foci of an ellipse is 6 and the length of the minor axis is 8, then the eccentricity is
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\(b^2 = a^2(1 - e^2)\) and \(2ae\) = distance between foci.
Updated On: Apr 7, 2026
- \(\frac{1}{\sqrt{5}}\)
- \(\frac{1}{2}\)
- \(\frac{3}{5}\)
- \(\frac{4}{5}\)
Show Solution
The Correct Option is C
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