If the base of an isosceles triangle is \(3\sqrt{2}\) feet and the two equal sides are increasing at the rate of \(1\) ft/s, then the rate of increase of its area (in sq.ft/sec) when the angle between the equal sides is a right angle is
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For related rates involving triangles, first use the geometric condition to determine the instantaneous dimensions of the figure. Only then differentiate the area formula with respect to time.