\(4 \sqrt6\)
\(6 \sqrt6\)
\(2 \sqrt6\)
\(\sqrt6\)
Analysis:
The area of an equilateral triangle with side length \( a \) is calculated using the formula: \[ \text{Area of triangle} = \frac{\sqrt{3}}{4} a^2 \]
For an equilateral triangle with a side length of 12 cm, the area is: \[ \text{Area} = \frac{\sqrt{3}}{4} (12^2) = 36\sqrt{3} \] square centimeters.
A regular hexagon with side length \( s \) can be divided into 6 equilateral triangles, each with a side length of \( s \).
The area of one such equilateral triangle is: \[ \text{Area of one triangle} = \frac{\sqrt{3}}{4} s^2 \]
The total area of the hexagon, being the sum of the areas of these 6 triangles, is: \[ \text{Area of hexagon} = 6 \times \frac{\sqrt{3}}{4} s^2 = \frac{3\sqrt{3}}{2} s^2 \]
Given that the hexagon's area equals the area of the equilateral triangle with a side of 12 cm: \[ \frac{3\sqrt{3}}{2} s^2 = 36\sqrt{3} \]
Solving for \( s^2 \): \[ s^2 = 24 \]
Solving for \( s \): \[ s = 2\sqrt{6} \]
Conclusion: The side length of the hexagon is 2√6.