Question:medium

If $(\sqrt{3} - i)^{50} = 2^{48}(x - iy)$, then $x^{2} + y^{2}$ equals

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Polar form shortcut: $(\sqrt{3}-i)^n = 2^n(\cos(n\pi/6) - i\sin(n\pi/6))$ (using angle $-\pi/6$). Reduce the angle modulo $2\pi$.
Updated On: Apr 8, 2026
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The Correct Option is D

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