Question:medium
If \( \sin\!\left(\tan^{-1}(x\sqrt2)\right)=\cot\!\left(\sin^{-1}\!\sqrt{1-x^2}\right),\; x\in(0,1) \), then the value of \(x\) is :
If \( \sin\!\left(\tan^{-1}(x\sqrt2)\right)=\cot\!\left(\sin^{-1}\!\sqrt{1-x^2}\right),\; x\in(0,1) \), then the value of \(x\) is :
Updated On: Apr 12, 2026
- \( \frac12 \)
- \( \frac13 \)
- \( \frac23 \)
- \( \frac58 \)
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The Correct Option is C
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