Question:medium

If $p^{3}=q^{4}=r^{6}=t^{7}=s^{2}$, then $\log_{t}(pqrs)=......$

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When variables are equal to each other, raising them to fractional powers of a single base is the easiest substitution.
Updated On: Jun 19, 2026
  • $168/5$
  • $28$
  • $31/4$
  • $35/4$
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Understanding the Question:
We need to express $p, q, r, s$ in terms of $t$ to evaluate the logarithm.

Step 2: Key Formula or Approach:

Property: If $x^a = y^b$, then $x = y^{\frac{b}{a}}$.
Property: $\log_{x^n}(x^m) = \frac{m}{n}$.

Step 3: Detailed Explanation:

Let $p^3 = q^4 = r^6 = t^7 = s^2 = k$.
Then:
$p = k^{\frac{1}{3}}$, $q = k^{\frac{1}{4}}$, $r = k^{\frac{1}{6}}$, $t = k^{\frac{1}{7}}$, $s = k^{\frac{1}{2}}$.
Now calculate the product $pqrs$: \[ pqrs = k^{\frac{1}{3} + \frac{1}{4} + \frac{1}{6} + \frac{1}{2}} \] The LCM of denominators $(3, 4, 6, 2)$ is $12$: \[ pqrs = k^{\frac{4 + 3 + 2 + 6}{12}} = k^{\frac{15}{12}} = k^{\frac{5}{4}} \] We need $\log_t(pqrs)$: \[ \log_{k^{1/7}}(k^{5/4}) = \frac{5/4}{1/7} = \frac{5}{4} \times 7 = \frac{35}{4} \]

Step 4: Final Answer:

The value is $\frac{35}{4}$.
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