Question:medium

If $\omega$ is an imaginary cube root of 1, then $(1+\omega-\omega^2)^5 + (1-\omega+\omega^2)^5$ is equal to

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$\omega^3=1$, $1+\omega+\omega^2=0$.
Updated On: Apr 8, 2026
  • $16$
  • $8$
  • $9$
  • $32$
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The Correct Option is D

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