Question:medium

If \(\omega\) is a complex cube root of unity, then \[ (1+\omega)(1+\omega^2)(1+\omega^4)(1+\omega^5)(1+\omega^7)(1+\omega^8)\cdots \] (2n factors) is equal to

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Whenever powers of cube roots of unity appear, reduce exponents modulo 3. This usually converts long products into simple repeating factors.
Updated On: Jun 18, 2026
  • \(-1\)
  • \(0\)
  • \(1\)
  • \(2\)
Show Solution

The Correct Option is C

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