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If \( n, K \in \mathbb{N} \) such that \( n \neq 3K \), then \( (\sqrt{3}+i)^{2n} + (\sqrt{3}-i)^{2n} = \)
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Checking specific small values for \( n \) (like \( n=1 \) and \( n=2 \)) is a fast way to verify the formula from the options in competitive exams.
TS EAMCET - 2025
TS EAMCET
Updated On:
Mar 27, 2026
\( (-1)^n 2^{2n+1} \)
\( (-1)^{n+1} 2^{2n+1} \)
\( (-1)^{n+1} 2^{2n} \)
\( (-1)^{n+1} 2^n \)
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The Correct Option is
C
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