Question:medium

If \( \lim_{x \to \frac{\pi}{2}} \dfrac{b(1 - \sin x)(\pi - 2x)^2}{1} = \frac{1}{3} \), then \( \int_0^{3b-6} |x^2 + 2x - 3| \, dx \) is equal to:

Updated On: Apr 9, 2026
  • 3
  • 4
  • \(\frac{7}{4}\)
  • 2
Show Solution

The Correct Option is B

Solution and Explanation

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