Question:medium

If $\int \frac{1}{(x+100)\sqrt{x+99}} dx = f(x) + c$ then $f(x) =$

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For integrals of the form $\frac{1}{(ax+b)\sqrt{cx+d}}$, the substitution $u = \sqrt{cx+d}$ usually leads to an arctan or log form.
  • $2\sqrt{x+100}$
  • $3\sqrt{x+100}$
  • $2 \tan^{-1}\sqrt{x+99}$
  • $2 \tan^{-1}\sqrt{x+100}$
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The Correct Option is C

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