Question:medium

If in English Alphabet 'e' and every alternate letter from 'e' onwards is written in Capitals, then how will sixth month from March will be coded

Updated On: Jul 15, 2026
  • SEPTEmbER
  • SEptEMbEr
  • SepTeMber
  • SEPtEmbER
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The Correct Option is B

Approach Solution - 1

Step 1: List the letters that must become capitals, starting at 'e' and taking every alternate letter onward: e, g, i, k, m, o, q, s, u, w, y; every other letter of the alphabet stays lower-case.

Step 2: Identify the target word: the sixth month counted from March (April = 1st, May = 2nd, June = 3rd, July = 4th, August = 5th, September = 6th) is September, so the base word is 'september'.

Step 3: Mark each letter of 'september' against the capital set: s, e, m, e are in the set so they become S, E, M, E, while p, t, b, r are not in the set so they stay lower-case.

Step 4: Assemble the letters in order, S, E, p, t, E, M, b, E, r, to get the coded word SEptEMbEr.
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Approach Solution -2

The rule can also be pictured as pairing up the alphabet from 'e' onward into two-letter blocks, (e,f), (g,h), (i,j), (k,l), (m,n), (o,p), (q,r), (s,t), (u,v), (w,x), (y,z), where only the first letter of each pair is capitalised and the second stays lower-case; a, b, c, d, before 'e', are never capitalised. The sixth month from March is September, so 'september' is checked pair by pair: s falls in the pair (s,t), taking the capital first slot, while t takes the lower-case second slot; e falls in the pair (e,f), taking the capital first slot; m falls in the pair (m,n), taking the capital first slot; b falls before the paired region entirely, so it stays lower-case; the repeated e is again the first of its own pair, so it is capital; r falls in the pair (q,r), taking the lower-case second slot.

  1. Option A (SEPTEmbER): treats p as the first letter of the (o,p) pair and capitalises it, but p is the second letter of that pair; it also wrongly capitalises the final r, the second letter of the (q,r) pair.
  2. Option B (SEptEMbEr): s (first of s,t) capital, t (second of s,t) lower, e (first of e,f) capital, m (first of m,n) capital, b (before the paired region) lower, e capital, r (second of q,r) lower, every letter lands on the correct side of its pair.
  3. Option C (SepTeMber): capitalises t, the second letter of the (s,t) pair, when only the first letter s should be capital, and leaves the repeated e in lower-case though e always heads its own pair.
  4. Option D (SEPtEmbER): capitalises p, the second letter of the (o,p) pair, and also capitalises the final r, the second letter of the (q,r) pair, both of which should stay lower-case.

Only option B places every letter of 'september' on the correct side of its pairing.

Therefore, the correct answer is SEptEMbEr.

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