Question:medium

If in a certain code, `Clever` is written as `XOVEVI`, then `Smart` would be written as

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When one example perfectly fits the Atbash mapping (A↔Z, B↔Y, ..., M↔N), apply it directly to the target word.
Updated On: Jul 15, 2026
  • HZNGI
  • HNZIG
  • GHNGI
  • GIHZN
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The Correct Option is B

Approach Solution - 1

Step 1: Understanding the Concept:
Each letter in the code is swapped for the letter that sits the same distance from the end of the alphabet as the original sits from the start. A becomes Z, B becomes Y, C becomes X, and so on toward the middle of the alphabet.

Step 2: Key Formula or Approach:
For any letter, its code position plus its mirror position always add up to 27, since there are 26 letters. So if a letter is in position \(n\), its mirror letter is in position \(27-n\).

Step 3: Detailed Explanation:
Checking the example: C is in position 3, so its mirror is position \(27-3=24\), which is X. This matches Clever becoming XOVEVI letter for letter.
Now apply the same rule to SMART: S is position 19, mirror is \(27-19=8\), which is H. M is position 13, mirror is \(27-13=14\), which is N. A is position 1, mirror is \(27-1=26\), which is Z. R is position 18, mirror is \(27-18=9\), which is I. T is position 20, mirror is \(27-20=7\), which is G.
Reading these in order gives H, N, Z, I, G.

Step 4: Final Answer:
SMART is coded as HNZIG.
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Approach Solution -2

Step 1: Locate the centre of the alphabet.
The 26 letters split evenly around the boundary between M (13th letter) and N (14th letter). Every mirror pair sits an equal number of steps out from this centre on either side.

Step 2: Confirm the pattern using the given example.
C is 10 steps before M, and its pair X is 10 steps after N, both landing the same distance from the centre. Likewise E is 8 steps before M, and its pair V is 8 steps after N. This confirms letters are mirrored symmetrically around the M-N boundary.

Step 3: Apply the same reflection to SMART.
S is 5 steps after N (N, O, P, Q, R, S), so its mirror is 5 steps before M, which is H. M is exactly at the centre boundary on the first side, and its mirror is N. A is 12 steps before M, so its mirror is 12 steps after N, which is Z. R is 4 steps after N, so its mirror is 4 steps before M, which is I. T is 6 steps after N, so its mirror is 6 steps before M, which is G.

Step 4: Final Answer:
Reading the mirrors of S, M, A, R, T in order gives H, N, Z, I, G, so SMART is coded as HNZIG.
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