Question:medium

If in a certain code, 'Clever; is written as 'XOVEVI', then 'Smart' would written as

Updated On: Jul 15, 2026
  • HZNGI
  • HNZIG
  • GHNGI
  • GIHZN
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The Correct Option is B

Approach Solution - 1

Step 1: Confirm the rule from the example: CLEVER at positions 3,12,5,22,5,18 becomes XOVEVI at positions 24,15,22,5,22,9, and each coded position equals 27 minus the original position, so the cipher mirrors the alphabet (A↔Z, B↔Y, C↔X, and so on).

Step 2: List the positions of the letters in 'SMART': S = 19, M = 13, A = 1, R = 18, T = 20.

Step 3: Apply 27 minus position to each: \(27-19=8\) = H, \(27-13=14\) = N, \(27-1=26\) = Z, \(27-18=9\) = I, \(27-20=7\) = G.

Step 4: Reading the coded letters in order gives HNZIG.
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Approach Solution -2

Since 'Clever' at positions 3, 12, 5, 22, 5, 18 codes to 'XOVEVI' at positions 24, 15, 22, 5, 22, 9, adding each original position to its coded position always gives 27, as in \(3+24=27\), \(12+15=27\), \(5+22=27\), \(22+5=27\), \(18+9=27\). This gives a quick check: an option is only valid if, letter by letter, its position plus SMART's corresponding letter's position equals 27. SMART's positions are S = 19, M = 13, A = 1, R = 18, T = 20.

  1. Option A (HZNGI): H = 8 against S = 19 gives \(19+8=27\), which checks out, but Z = 26 against M = 13 gives \(13+26=39\), not 27, so the check fails partway through.
  2. Option B (HNZIG): H = 8 with S = 19 gives 27, N = 14 with M = 13 gives 27, Z = 26 with A = 1 gives 27, I = 9 with R = 18 gives 27, G = 7 with T = 20 gives 27, every pair sums to 27.
  3. Option C (GHNGI): G = 7 against S = 19 gives \(19+7=26\), one short of 27, so the very first pair already fails the check.
  4. Option D (GIHZN): G = 7 against S = 19 gives 26, not 27, failing the check at the first letter as well.

Only option B satisfies the sum-to-27 pairing at every one of the five letters.

Therefore, the correct answer is HNZIG.

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