Question:medium

If for $x\ne0$ and $f(x)=x^{3}sin\frac{1}{x}, f(0)=0$ then $f(x)$ is}

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(Zero) $\times$ (Bounded) = Zero. This makes such functions continuous at the origin.

Updated On: Jul 3, 2026

Discontinuous at $x\ne0$
Continuous for all values of x
Discontinuous at $x=0$
Discontinuous for all values of x

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The Correct Option is B

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