Question:medium
If $f(x) = \min \{2x^2 + 3, 6x\} + |x-1| \cos(x^2 - \frac{1}{4})$, then the number of points of non derivability of $f(x)$ is/are
If $f(x) = \min \{2x^2 + 3, 6x\} + |x-1| \cos(x^2 - \frac{1}{4})$, then the number of points of non derivability of $f(x)$ is/are
Updated On: Apr 6, 2026
- 1
- 2
- 3
- 4
Show Solution
The Correct Option is C
Solution and Explanation
Was this answer helpful?
0
Top Questions on Limits
- Marks of 5 students of a group are \( 8, 12, 13, 15, 22 \). Find the variance.
- Evaluate \( \int_{0}^{\pi/4} \frac{\cos^2 x}{\cos^2 x + 4 \sin^2 x} \, dx \):
The area of the region \( \{(x, y): 0 \leq y \leq x^2 + 1, \, 0 \leq y \leq x + 1, \, 0 \leq x \leq 2\ \) is:}
- The limit of \( \lim_{x \to 0} \frac{\sin x}{x} \) is:
- Want to practice more? Try solving extra ecology questions todayView All Questions
