The function's property is given as \(f(5+x) = f(5-x)\) for all real \(x\).
This indicates symmetry around the line \(x = 5\). Consequently, if \(a\) is a root, \(10-a\) must also be a root.
Given that \(f(x)=0\) has four distinct real roots, denoted \(r_1, r_2, r_3, r_4\). Their symmetric pairings are:
Each symmetric pair of roots sums to 10. Therefore, the sum of all four roots is:
\(10 + 10 = 20\).
The sum of the four distinct real roots equals 20.