Question:medium

If \(\displaystyle \lim_{x\to\infty}x\sin\!\left(\frac1x\right)=A\) and \(\displaystyle \lim_{x\to0}x\sin\!\left(\frac1x\right)=B\), then which one of the following is correct?

Show Hint

Use standard limit \(\displaystyle \lim_{u\to0}\frac{\sin u}{u}=1\).
Updated On: Mar 23, 2026
  • \(A=1\) and \(B=0\)
  • \(A=0\) and \(B=1\)
  • \(A=0\) and \(B=0\)
  • \(A=1\) and \(B=1\)
Show Solution

The Correct Option is A

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