If \(\displaystyle \lim_{x\to\infty}x\sin\!\left(\frac1x\right)=A\) and \(\displaystyle \lim_{x\to0}x\sin\!\left(\frac1x\right)=B\), then which one of the following is correct?
Show Hint
Use standard limit \(\displaystyle \lim_{u\to0}\frac{\sin u}{u}=1\).