If both the roots of the equation
\[
x^2-2ax+a^2-1=0 \quad (a\in\mathbb{R})
\]
lie in the interval \((-2,2)\), then the equation
\[
x^2-(a^2+1)x-(a^2+2)=0
\]
has:
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When roots are restricted to an interval, first determine the parameter range,
then use sign analysis of the polynomial to locate roots in specific subintervals.