Question:medium

If both the roots of the equation \[ x^2-2ax+a^2-1=0 \quad (a\in\mathbb{R}) \] lie in the interval \((-2,2)\), then the equation \[ x^2-(a^2+1)x-(a^2+2)=0 \] has:

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When roots are restricted to an interval, first determine the parameter range, then use sign analysis of the polynomial to locate roots in specific subintervals.
Updated On: Mar 25, 2026
  • both roots in \((-3,0)\)
  • one root in \((0,2)\) and another root in \((-2,0)\)
  • one root in \((2,3)\) and another root in \((-2,0)\)
  • one root in \((-3,-2)\) and another root in \((0,2)\)
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The Correct Option is C

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