Step 1: Understanding the Concept:
The problem involves the rotation of a vector in a specific plane within a 3D coordinate system.
A vector \(\vec{v}\) originally lies along the \(x\)-axis. Its initial coordinates are \((3, 0, 0)\).
It is rotated in the \(x-z\) plane. An observer looking from the \(+y\) axis sees the \(x-z\) plane as their field of view.
In a standard right-handed coordinate system, looking from the \(+y\) axis down to the origin, the \(x\)-axis points to the right and the \(z\)-axis points upward in that view.
Rotating "clockwise" with respect to the \(x\)-axis from the \(+y\) observer's perspective means the vector moves from the positive \(x\)-axis toward the positive \(z\)-axis.
Step 2: Key Formula or Approach:
For a vector of magnitude \(A\) rotated by angle \(\theta\) in a plane:
Component along starting axis = \(A \cos\theta\).
Component along the axis it is rotating towards = \(A \sin\theta\).
Step 3: Detailed Explanation:
The magnitude of the vector is \(|\vec{v}| = 3\).
Initially, it is along the \(+x\) direction (\(3\hat{i}\)).
The rotation takes place in the \(x-z\) plane.
When viewed from the \(+y\) axis, the standard 2D axes are \(x\) (horizontal) and \(z\) (vertical).
A clockwise rotation by angle \(\theta\) starting from the positive \(x\)-axis tilts the vector towards the positive \(z\)-axis.
The new \(x\)-component will be:
\[ v_x = 3 \cos\theta \]
The new \(z\)-component will be:
\[ v_z = 3 \sin\theta \]
Since there is no rotation or movement along the \(y\)-axis, the \(y\)-component remains zero.
Writing the vector in unit vector notation:
\[ \vec{v}_{new} = (3 \cos\theta)\hat{i} + (0)\hat{j} + (3 \sin\theta)\hat{k} \]
\[ \vec{v}_{new} = 3\cos\theta \hat{i} + 3\sin\theta \hat{k} \]
This matches option (D).
Step 4: Final Answer:
The vector is resolved into its components along the \(x\) and \(z\) axes after the rotation, yielding \(3\cos\theta \hat{i} + 3\sin\theta \hat{k}\).