If a solid sphere of mass \(2\) kg is rolling without slipping on a surface with a velocity of
\[
10\ \mathrm{ms^{-1}},
\]
then the total kinetic energy of the sphere is
Show Hint
For a solid sphere rolling without slipping,
\[
\boxed{
K=\frac12mv^2+\frac12I\omega^2
=\frac{7}{10}mv^2.
}
\]
Always use
\[
\boxed{\omega=\frac vr.}
\]