The provided equation:
\[ \frac{a}{100} \times a + \frac{b}{100} \times b = \frac{2}{100} \times ab \]
Simplified:
\[ \frac{a^2}{100} + \frac{b^2}{100} = \frac{2ab}{100} \]
Multiply both sides by 100:
\[ a^2 + b^2 = 2ab \]
Rearrange:
\[ a^2 - 2ab + b^2 = 0 \]
Factor:
\[ (a - b)^2 = 0 \]
Therefore:
\[ a = b \]
Consequently, \( b \) equals \( a \), meaning \( b \) is 100% of \( a \).
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