Question

If $A$ and $B$ are two events such that $P(A) = \dfrac{1}{2}$, $P(B) = \dfrac{1}{3}$ and $P(A \mid B) = \dfrac{1}{4}$ then $P(A' \cap B')$ is:

• A. $\frac{1}{4}$
• B. $\frac{1}{12}$
• C. $\frac{3}{16}$
• D. $\frac{1}{8}$

Hint:

$P(A' \cap B')$ is the probability that "None" of the events happen. In a Venn diagram, this is the area outside both circles.

Answer 1

The Correct Option is A