Question:medium

If a=3, b=5, c=7 are the sides of a triangle ABC, then $ \cot A + \cot B + \cot C = $

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The formula $ \cot A + \cot B + \cot C = \frac{a^2+b^2+c^2}{4\Delta} $ is a very powerful tool for problems involving the sum of cotangents. Memorizing it can save a lot of time compared to finding each angle individually using the Law of Cosines.

Updated On: Mar 30, 2026

$ \frac{15\sqrt{3}}{4} $
$ \frac{7}{\sqrt{3}} $
$ \frac{83}{15\sqrt{3}} $
$ \frac{83\sqrt{3}}{15} $

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The Correct Option is C

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If a=3, b=5, c=7 are the sides of a triangle ABC, then \( \cot A + \cot B + \cot C = \)

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The Correct Option is C

Solution and Explanation

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