Question

Identify the CORRECT set of details from the following: 
A. \([\text{Co}(\text{NH}_3)_6]^{3+}\): Inner orbital complex; \(d^2sp^3\) hybridized 
B. $[\text{MnCl}_6]^{3-}$: Outer orbital complex; $sp^3d^2$ hybridized 
C. $[\text{CoF}_6]^{3-}$: Outer orbital complex; $d^2sp^3$ hybridized 
D. $[\text{FeF}_6]^{3-}$: Outer orbital complex; $sp^3d^2$ hybridized 
E. $[\text{Ni}(\text{CN})_4]^{2-}$: Inner orbital complex; $sp^3$ hybridized}

• A. A, B, C, D & E
• B. C & D Only
• C. A, B & D Only
• D. A, C & E Only

Hint:

Hybridization types: $d^2sp^3$ (Inner Octahedral), $sp^3d^2$ (Outer Octahedral), $dsp^2$ (Square Planar), $sp^3$ (Tetrahedral).

Answer 1

The Correct Option is C

To determine the correct set of details about the given complexes, we need to analyze each option based on the coordination chemistry principles such as hybridization, crystal field theory, and the nature of the ligands:

• A. \([\text{Co}(\text{NH}_3)_6]^{3+}\): This is an inner orbital or low-spin complex. Here, cobalt is in the +3 oxidation state with an electronic configuration of \(3d^6\). The strong field ligand \(\text{NH}_3\) pairs up the electrons in the 3d subshell resulting in \(d^2sp^3\) hybridization; thus, this statement is correct.
• B. \([\text{MnCl}_6]^{3-}\): Manganese is in the +3 oxidation state with the electronic configuration of \(3d^4\). Chloride is a weak field ligand, leading to an outer orbital or high spin complex with \(sp^3d^2\) hybridization; hence, this statement is correct.
• C. \([\text{CoF}_6]^{3-}\): Here, cobalt is present in the +3 oxidation state with \(3d^6\) configuration. \(\text{F}^-\text{}\) is a weak field ligand, leading to an outer orbital complex with \(sp^3d^2\) hybridization, not \(d^2sp^3\) as suggested; thus, this statement is incorrect.
• D. \([\text{FeF}_6]^{3-}\): Iron is in the +3 oxidation state with an electronic configuration of \(3d^5\). \(\text{F}^-\text{}\) is a weak field ligand, leading to an outer orbital complex with \(sp^3d^2\) hybridization; hence, this statement is correct.
• E. \([\text{Ni}(\text{CN})_4]^{2-}\): Nickel in this complex is in the +2 oxidation state with the electronic configuration of \(3d^8\). \(\text{CN}^-\text{}\) is a strong field ligand resulting in an inner orbital complex with \(dsp^2\) hybridization, not \(sp^3\); thus, this statement is incorrect.

Based on the above analysis: 

Complex	Complex Type	Hybridization	Correctness
\([\text{Co}(\text{NH}_3)_6]^{3+}\)	Inner	\(d^2sp^3\)	Correct
\([\text{MnCl}_6]^{3-}\)	Outer	\(sp^3d^2\)	Correct
\([\text{CoF}_6]^{3-}\)	Outer	\(sp^3d^2\)	Incorrect
\([\text{FeF}_6]^{3-}\)	Outer	\(sp^3d^2\)	Correct
\([\text{Ni}(\text{CN})_4]^{2-}\)	Inner	\(dsp^2\)	Incorrect

Therefore, the correct answer is: A, B & D Only.