Step 1: Understanding the Question:
This is a multi-step organic synthesis starting from a carboxylic acid. Step 3: Detailed Explanation:
Step 1: Acetic acid (\( \text{CH}_3\text{COOH} \)) reacts with thionyl chloride (\( \text{SOCl}_2 \)) to form an acyl chloride.
\( \text{CH}_3\text{COOH} + \text{SOCl}_2 \rightarrow \text{CH}_3\text{COCl (A)} + \text{SO}_2 + \text{HCl} \).
Compound 'A' is Acetyl chloride.
Step 2: Acetyl chloride reacts with Ammonia (\( \text{NH}_3 \)) to form an amide.
\( \text{CH}_3\text{COCl} + \text{NH}_3 \rightarrow \text{CH}_3\text{CONH}_2 \text{ (B)} + \text{HCl} \).
Compound 'B' is Acetamide. Step 4: Final Answer:
The product 'B' is Acetamide.