Question:medium

How many grams of metallic mercury could be produced approximately by electrolysing a \(1.0\,\mathrm{M}\) \(\mathrm{Hg(NO_3)_2}\) solution with a current of \(2.0\,\mathrm{A}\) for \(3.0\,\mathrm{h}\)? 
\[ \begin{aligned} &\text{Given:} \\ &\text{Molar mass of Hg} = 200\,\mathrm{g\,mol^{-1}},\\ &F = 96500\,\mathrm{C\,mol^{-1}} \end{aligned} \]

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Faraday's first law: \[ \boxed{ m=\frac{MQ}{nF} =\frac{MIt}{nF}. } \] Here, \(n\) is the number of electrons involved in the electrode reaction.
Updated On: Jul 21, 2026
  • \(22.4\,\mathrm{g}\)
  • \(20.1\,\mathrm{g}\)
  • \(11.2\,\mathrm{g}\)
  • \(40.2\,\mathrm{g}\)
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The Correct Option is A

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