Consider the following compounds:
(i) CH₃CH₂Br
(ii) CH₃CH₂CH₂Br
(iii) CH₃CH₂CH₂CH₂Br
Arrange the compounds in the increasing order of their boiling points.
(iii) < (ii) < (i)
Step 1: Understanding boiling points. Boiling point is influenced by molecular size and intermolecular forces. Longer carbon chains result in higher boiling points.
Step 2: Analysis of the compounds.
- Compound (i) CH_3CH_2Br: Shorter chain, thus lower boiling point.
- Compound (ii) CH_3CH_2CH_2Br: Longer chain, leading to a higher boiling point than (i).
- Compound (iii) CH_3CH_2CH_2Br: Although structurally similar to (ii), this compound exhibits the highest boiling point due to its largest molecular size.
Step 3: Conclusion. The boiling points are ordered as (i) < (ii) < (iii), aligning with option (B).
Assertion (A): The boiling points of alkyl halides decrease in the order: RI>RBr>RCl>RF.
Reason (R): The boiling points of alkyl chlorides, bromides and iodides are considerably higher than that of the hydrocarbon of comparable molecular mass.
Arrange the following compounds in increasing order of their boiling point: \[ \text{(CH}_3\text{)}_2\text{NH, CH}_3\text{CH}_2\text{NH}_2, \text{CH}_3\text{CH}_2\text{OH} \]