Question

Highest oxidation state of $Mn$ is exhibited in $Mn _2 O _7$ The correct statements about $Mn _2 O _7$ are
(A) Mn is tetrahedrally surrounded by oxygen atoms
(B) $Mn$ is octahedrally surrounded by oxygen atoms
(C) Contains $Mn-O-Mn$ bridge
(D) Contains $Mn - Mn$ bond
Choose the correct answer from the options given below:

• A. A and D only
• B. A and C only
• C. B and C only
• D. B and D only

Answer 1

The Correct Option is B

The compound in question is Mn_2O_7, which is known for having manganese in its highest oxidation state of +7. To determine the correct statements about Mn_2O_7, let's analyze the structure and bonding:

1. Structure of Mn_2O_7: Each manganese atom is surrounded by oxygen atoms. Specifically, it is tetrahedrally coordinated by four oxygen atoms, forming a part of the anion structure. This suggests that statement (A) is correct.
2. Mn_2O_7 has a bridge structure where two MnO₄ units are connected through an oxygen bridge. This means there is a Mn-O-Mn bond present. Thus, statement (C) is also correct.
3. The statement that manganese is octahedrally surrounded by oxygen atoms is incorrect because, in a tetrahedral arrangement, each manganese atom is bonded to four oxygens directly. Thus, statement (B) is incorrect.
4. There is no direct Mn-Mn bond in Mn_2O_7. Instead, the manganese atoms are connected via an oxygen bridge. Therefore, statement (D) is incorrect.

Based on this analysis, the correct statements about Mn_2O_7 are (A) and (C). Hence, the correct answer is 'A and C only'.