Question:medium

Given below are two statements:
Statement I: The second ionisation enthalpy of Na is larger than the corresponding ionisation enthalpy of Mg.
Statement II: The ionic radius of $O^{2-$ is larger than that of $F^-$.}

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For isoelectronic species, the anion with the smallest nuclear charge (Z) has the largest ionic radius.
Updated On: Feb 24, 2026
  • Statement I is true but Statement II is false
  • Statement I is false but Statement II is true
  • Both Statement I and Statement II are true
  • Both Statement I and Statement II are false
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The Correct Option is C

Solution and Explanation

To determine the correctness of the statements given, we should evaluate each one based on known chemical principles and periodic trends.

  1. Statement I: The second ionisation enthalpy of Na is larger than the corresponding ionisation enthalpy of Mg.
    • The first ionisation enthalpy removes one electron, and for sodium (Na), this electron is removed from a singly filled 3s orbital, resulting in the Na+ ion, which has a full 2s and 2p subshell, making it very stable (like the noble gas neon).
    • The second ionisation enthalpy involves removing an electron from this stable Na+ ion, making it exceedingly difficult because of the full subshell and stable electronic configuration. Therefore, the second ionisation enthalpy of Na is indeed very high.
    • For magnesium (Mg), the first ionisation removes an electron to form Mg+, which still has valence electrons left. The second ionisation removes one more electron to form Mg2+, which corresponds to the stable electronic configuration of neon.
    • Given these configurations, the second ionisation enthalpy of Na is indeed larger than that of Mg because the electrons removed from Mg+ are still within the same energy shell (3s), whereas removing an electron from Na+ disrupts a filled shell. Hence, Statement I is true.
  2. Statement II: The ionic radius of O2− is larger than that of F.
    • Both O2− and F are formed by gaining electrons to achieve stable configurations similar to the noble gas neon, but they originate from different atoms with different original electron counts.
    • Oxygen gains 2 electrons to form O2−, resulting in a configuration of [He] 2s² 2p⁶. Fluorine gains 1 electron to form F, also achieving a configuration of [He] 2s² 2p⁶.
    • However, for O2−, there is increased electron-electron repulsion due to the additional electron compared to F. This repulsion leads to a greater ionic radius for O2− compared to F. Hence, Statement II is true.

Therefore, both Statement I and Statement II are correct. The correct option is: Both Statement I and Statement II are true.

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