Question:medium

Given below are two statements: 
Statement I: Mohr's salt is composed of only three types of ions—ferrous, ammonium, and sulphate. 
Statement II: If the molar conductance at infinite dilution of ferrous, ammonium, and sulphate ions are $ x_1 $, $ x_2 $, and $ x_3 $ $ \text{S cm}^2 \, \text{mol}^{-1} $, respectively, then the molar conductance for Mohr's salt solution at infinite dilution would be given by $ x_1 + x_2 + 2x_3 $.

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When calculating molar conductance at infinite dilution for ionic compounds, remember that each ion contributes to the total conductance according to its molar conductance, without any extra multiplication unless the ion is polyatomic and contributes differently.
Updated On: Mar 25, 2026
  • Both statements I and Statement II are false
  • Statement I is false but Statement II is true
  • Statement I is true but Statement II is false
  • Both statements I and Statement II are true
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The Correct Option is C

Solution and Explanation

Step 1: Analysis of Statement I
Mohr's salt comprises three ions: ferrous (\( \text{Fe}^{2+} \)), ammonium (\( \text{NH}_4^+ \)), and sulphate (\( \text{SO}_4^{2-} \)).
This statement is accurate as Mohr's salt, also known as ammonium ferrous sulphate, exclusively contains these three ionic species.
Consequently, Statement I is correct.
Step 2: Analysis of Statement II
The molar conductance of a salt at infinite dilution equals the sum of the molar conductances of its constituent ions. For Mohr's salt, the relevant ions are:
Ferrous ion (\( \text{Fe}^{2+} \)) with molar conductance \( x_1 \), Ammonium ion (\( \text{NH}_4^+ \)) with molar conductance \( x_2 \), and Sulphate ion (\( \text{SO}_4^{2-} \)) with molar conductance \( x_3 \). At infinite dilution, the total molar conductance (\( \lambda_{\infty} \)) of Mohr's salt should be the sum of the conductances of these ions. However, Statement II inaccurately assigns a coefficient to the sulphate ion. The sulphate ion (\( \text{SO}_4^{2-} \)) is a monoatomic ion and should contribute \( x_3 \) to the total conductance, not \( 2x_3 \). 
Thus, the correct formulation for molar conductance is: \[ \lambda_{\infty} = x_1 + x_2 + x_3 \] 
Therefore, Statement II is erroneous due to the incorrect doubling of the sulphate ion's contribution.

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