Lassaigne's test is employed to detect elements such as nitrogen, sulfur, and halogens within organic compounds. The following statements are analyzed in this context.
- Statement I: "In Lassaigne's test, the covalent organic molecules are transformed into ionic compounds."
- During Lassaigne's test, organic compounds undergo fusion with sodium metal. This process converts elements covalently bonded in organic molecules, including nitrogen, sulfur, and halogens, into water-soluble sodium salts, which are ionic compounds.
- For instance, nitrogen is converted into \(NaCN\), sulfur into \(Na_2S\), and halogens into sodium halides like \(NaCl\), \(NaBr\), or \(NaI\).
- This statement is accurate, as it correctly describes the transformation of covalent bonds into ionic compounds during the test.
- Statement II: "The sodium fusion extract of an organic compound having N and S gives Prussian blue color with FeSO4 and Na4[Fe(CN)6]."
- When both nitrogen and sulfur are present in an organic compound, the sodium fusion extract forms sodium thiocyanate, \(NaSCN\).
- In the presence of HCl, \(NaSCN\) reacts with \(FeSO_4\) to produce a blood-red color, signifying the co-existence of sulfur and nitrogen.
- A Prussian blue color typically indicates the presence of nitrogen alone, formed when \(FeSO_4\) is reacted with \(Na_4[Fe(CN)_6]\) after oxidation, but this is not the case when both sulfur and nitrogen are present.
- Consequently, this statement is incorrect because the observed color in the presence of both N and S is blood-red, not Prussian blue.
Based on this analysis, the correct conclusion is: Statement I is true, while Statement II is false.