Question

Given below are two statements:
Statement I : Ethene at 333 to 343 K and 6-7 atm pressure in the presence of AIEt₃ and TiCl₄ undergoes addition polymerization to give LDP.
Statement II: Caprolactam at 533-543 K in H₂O through step growth polymerizes to give Nylon 6.
In the light of the above statements, choose the correct answer from the options given below:

• A. Both Statement t and Statement II are false
• B. Statement I is true but Statement II is false
• C. Both Statement I and Statement II are true
• D. Statement I is false but Statement II is true

Answer 1

The Correct Option is D

To determine the correct answer, let's examine each statement individually.

• Statement I: Ethene at 333 to 343 K and 6-7 atm pressure in the presence of AlEt₃ (Triethylaluminum) and TiCl₄ undergoes addition polymerization to give LDP.

This statement suggests that ethene polymerization under the given conditions results in the formation of low-density polyethylene (LDP). However, in reality, high-density polyethylene (HDPE) is typically produced using such coordination catalysts (e.g., Ziegler-Natta catalysts like AlEt₃/TiCl₄). Low-density polyethylene (LDPE) is generally produced using free radical polymerization at high pressure (1000-3000 atm) and temperature (350-570 K). Therefore, Statement I is false.

• Statement II: Caprolactam at 533-543 K in H₂O through step growth polymerizes to give Nylon 6.

This statement describes the polymerization of caprolactam to form Nylon 6 via ring-opening polymerization and is accurately described. The process involves hydrolysis and polymerization at the given temperature range, utilizing a step-growth mechanism. Thus, Statement II is true.

Based on the analysis of the statements:

• Statement I is false but Statement II is true.

Therefore, the correct answer is: Statement I is false but Statement II is true.