
The dipole moment is a vector. For trans-2-butene, the substituent dipoles cancel due to equal magnitude and opposite direction, yielding a net dipole moment of zero (\(\mu = 0\)). Conversely, in the cis isomer, these dipoles do not cancel, rendering the molecule polar with \(\mu > 0\). Consequently, the cis isomer possesses a larger dipole moment than the trans isomer.
Cis isomer: \(\mu > 0\), Trans isomer: \(\mu = 0\).
Both the assertion and the reason are accurate, with the reason providing a correct explanation for the assertion.

