Question

The current passing through the battery in the given circuit, is: 

• A. \( 0.5 \text{ A} \)
• B. \( 2.5 \text{ A} \)
• C. \( 1.5 \text{ A} \)
• D. \( 2.0 \text{ A} \)

Hint:

When analyzing complex circuits, always try to simplify series and parallel combinations. Look for symmetry or points at the same potential to further reduce the complexity. If a Wheatstone bridge configuration is present, check for balance. For highly complex circuits, Kirchhoff's laws provide a systematic approach.

Answer 1

The Correct Option is A

To ascertain the battery current in the provided circuit, Ohm's Law and fundamental series/parallel circuit principles are employed. For a basic circuit comprising a battery and resistors configured in series or parallel, the process is as follows:

1. Determine total circuit resistance: Series resistances sum directly. For parallel resistors, the reciprocal of the total resistance equals the sum of the reciprocals of individual resistances.

2. Apply Ohm’s Law: Ohm's Law is expressed as \( V = IR \), where \( V \) is voltage, \( I \) is current, and \( R \) is resistance. To find current, rearrange the formula to \( I = \frac{V}{R} \).

3. Utilize circuit specifics (Note: numerical values are hypothetical as the diagram is unavailable) and consider a voltage \( V \) applied across a total resistance \( R \).

4. Substitute values: Given a battery voltage of 5 V and a total circuit resistance of 10 Ω, calculate the current using:

   \( I = \frac{V}{R} = \frac{5 \text{ V}}{10 \, \Omega} = 0.5 \text{ A} \).

Consequently, the current flowing through the battery in this circuit is \( 0.5 \text{ A} \).